CUET · MATHS · PYQ PAPER 2025
The general solution of the differential equation \(\frac{d y}{d x}=-4 x y^2\) is given by
- A \(2 x^2-y=C: C\) is an arbitrary constant
- B \(2 x^2-\frac{1}{y}=C: C\) is an arbitrary constant
- C \(2 x^2+\frac{1}{y^2}=C: C\) is an arbitrary constant
- D \(2 x^2+\frac{1}{y}=C: C\) is an arbitrary constant
Answer & Solution
Correct Answer
(B) \(2 x^2-\frac{1}{y}=C: C\) is an arbitrary constant
Step-by-step Solution
Detailed explanation
\(\frac{d y}{y^2} = -4x \, dx\) \(\int y^{-2} dy = \int -4x \, dx\) \(-\frac{1}{y} = -2x^2 + C\) \(2x^2 - \frac{1}{y} = C\)
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