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CUET · MATHS · PYQ PAPER 2025

The general solution of the differential equation \(\frac{d y}{d x}=-4 x y^2\) is given by

  1. A \(2 x^2-y=C: C\) is an arbitrary constant
  2. B \(2 x^2-\frac{1}{y}=C: C\) is an arbitrary constant
  3. C \(2 x^2+\frac{1}{y^2}=C: C\) is an arbitrary constant
  4. D \(2 x^2+\frac{1}{y}=C: C\) is an arbitrary constant
Verified Solution

Answer & Solution

Correct Answer

(B) \(2 x^2-\frac{1}{y}=C: C\) is an arbitrary constant

Step-by-step Solution

Detailed explanation

\(\frac{d y}{y^2} = -4x \, dx\) \(\int y^{-2} dy = \int -4x \, dx\) \(-\frac{1}{y} = -2x^2 + C\) \(2x^2 - \frac{1}{y} = C\)
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