CUET · MATHS · PYQ PAPER 2023
The general solution of the differential equation \((1+y) d x-2 x d y=0\) is :
- A \(x=C(1+y)^2\) ; where C is constant
- B \(x^2=C\left(1+y^2\right)\) ; where C is constant
- C \(x^2-y^2=C\) ; where C is constant
- D \(y=C+x^2 y\) ; where C is constant
Answer & Solution
Correct Answer
(A) \(x=C(1+y)^2\) ; where C is constant
Step-by-step Solution
Detailed explanation
\((1+y) d x = 2 x d y\) \(\frac{d x}{x} = \frac{2 d y}{1+y}\) \(\int \frac{1}{x} d x = \int \frac{2}{1+y} d y\) \(\ln|x| = 2 \ln|1+y| + \ln|C|\) \(\ln|x| = \ln|C(1+y)^2|\) \(x = C(1+y)^2\)
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