CUET · MATHS · PYQ PAPER 2023
The general solution of the differential equation \(\left(1+x^2\right) d y-x d x=0\) is :
- A \(\frac{e^{2 y}}{1+x^2}=C\)
- B \(e^{2 y}-\frac{1}{1+x}=C\)
- C \(2 y+\left(1+x^2\right)=\log C\)
- D \(y^2+\log \left(1+x^2\right)=C\)
(whwre C is constant of integration)
Answer & Solution
Correct Answer
(A) \(\frac{e^{2 y}}{1+x^2}=C\)
Step-by-step Solution
Detailed explanation
\(\left(1+x^2\right) d y=x d x\) \(\int d y = \int \frac{x}{1+x^2} d x\) \(y = \frac{1}{2} \ln \left(1+x^2\right) + C_1\) \(2y = \ln \left(1+x^2\right) + 2C_1\) \(2y - \ln \left(1+x^2\right) = 2C_1\) \(\ln \left(e^{2y}\right) - \ln \left(1+x^2\right) = 2C_1\)…
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