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CUET · MATHS · PYQ PAPER 2023

The function \(f(x)=\tan x-x\) for \(x \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)\) is :

  1. A increasing function
  2. B decreasing function
  3. C neither increasing nor decreasing function
  4. D decreasing in \(\left(\frac{-\pi}{2}, 0\right)\) and increasing in \(\left(0, \frac{\pi}{2}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(A) increasing function

Step-by-step Solution

Detailed explanation

\(f'(x) = \sec^2 x - 1\) \(f'(x) = \tan^2 x\) For \(x \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right)\), \(\tan^2 x \ge 0\). \(f'(x) = 0\) only at \(x=0\). The function is increasing function.