CUET · MATHS · PYQ PAPER 2023
The function \(f(x)=\tan x-x\) for \(x \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)\) is :
- A increasing function
- B decreasing function
- C neither increasing nor decreasing function
- D decreasing in \(\left(\frac{-\pi}{2}, 0\right)\) and increasing in \(\left(0, \frac{\pi}{2}\right)\)
Answer & Solution
Correct Answer
(A) increasing function
Step-by-step Solution
Detailed explanation
\(f'(x) = \sec^2 x - 1\) \(f'(x) = \tan^2 x\) For \(x \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right)\), \(\tan^2 x \ge 0\). \(f'(x) = 0\) only at \(x=0\). The function is increasing function.
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