CUET · MATHS · PYQ PAPER 2023
The function \(f(x)=\tan x-x\) for \(x \in\left(0, \frac{\pi}{2}\right)\) is :
- A increasing function
- B decreasing function
- C neither increasing nor decreasing function
- D strictly decreasing function
Answer & Solution
Correct Answer
(A) increasing function
Step-by-step Solution
Detailed explanation
\(f'(x) = \sec^2 x - 1\) \(f'(x) = \tan^2 x\) For \(x \in \left(0, \frac{\pi}{2}\right)\), \(\tan^2 x > 0\). The function is an increasing function.
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