CUET · MATHS · PYQ PAPER 2025
The function \(f(x)=\frac{x-2}{x+1}, x \neq-1\) is increasing when (Where \(R\) is a set of real numbers:
- A \(x \in R\)
- B \(x \in R -\{-1\}\)
- C \(x \in R -\{1,-1\}\)
- D \(x \in R -\{0\}\)
Answer & Solution
Correct Answer
(B) \(x \in R -\{-1\}\)
Step-by-step Solution
Detailed explanation
\(f'(x) = \frac{(x+1)(1) - (x-2)(1)}{(x+1)^2}\) \(f'(x) = \frac{3}{(x+1)^2}\) \(f'(x) > 0 \Rightarrow \frac{3}{(x+1)^2} > 0\) \((x+1)^2 > 0\) \(x+1 \neq 0\) \(x \neq -1\) \(x \in R - \{-1\}\)
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