CUET · MATHS · PYQ PAPER 2025
The function \(f(x)=x^2 e^{-2 x}\) increases on
- A \((-\infty, \infty)\)
- B (0,1)
- C \((-\infty, 0) \cup(1, \infty)\)
- D \((1, \infty)\)
Answer & Solution
Correct Answer
(B) (0,1)
Step-by-step Solution
Detailed explanation
\(f'(x) = 2xe^{-2x} - 2x^2e^{-2x} = 2xe^{-2x}(1-x)\) \(2xe^{-2x}(1-x) = 0 \Rightarrow x=0, x=1\) \(f'(x) > 0 \text{ for } x \in (0,1)\)
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