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CUET · MATHS · PYQ PAPER 2025

The function \(f(x)=x+\frac{1}{x}\) has

  1. A local maxima at \(x=-1\)
  2. B local minima at \(x=-1\)
  3. C local maxima at \(x=1\).
  4. D neither local maxima nor local minima
Verified Solution

Answer & Solution

Correct Answer

(A) local maxima at \(x=-1\)

Step-by-step Solution

Detailed explanation

\(f'(x) = 1 - \frac{1}{x^2}\) \(f'(x) = 0 \implies 1 - \frac{1}{x^2} = 0 \implies x^2 = 1 \implies x = \pm 1\) \(f''(x) = \frac{2}{x^3}\) \(f''(-1) = \frac{2}{(-1)^3} = -2 Local maxima at \(x=-1\)
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