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CUET · MATHS · PYQ PAPER 2023

The function \(f(x)=|x-1|\) is strictly increasing in the interval.

  1. A \((0,1)\)
  2. B \((-\infty, 0)\)
  3. C \((-\infty,-1)\)
  4. D \((1, \infty)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \((1, \infty)\)

Step-by-step Solution

Detailed explanation

\(f(x) = \begin{cases} x-1 & \text{if } x \ge 1 \\ 1-x & \text{if } x \(f'(x) = \begin{cases} 1 & \text{if } x > 1 \\ -1 & \text{if } x \(f(x)\) is strictly increasing when \(f'(x) > 0\). \(f'(x) = 1 > 0 \implies x > 1\) Interval: \((1, \infty)\)