ExamBro
ExamBro
CUET · MATHS · PYQ PAPER 2023

The function \(f(x)=\left\{\begin{array}{ll}\frac{x^2+2 x-3}{x-1}, & \text { if } x \neq 1 \\ 0, & \text { if } x=1\end{array}\right.\) is

  1. A Continuous at \(x=1\)
  2. B discontinuous at \(x=1\)
  3. C Continuous at each real number
  4. D discontinuous at each real number
Verified Solution

Answer & Solution

Correct Answer

(B) discontinuous at \(x=1\)

Step-by-step Solution

Detailed explanation

\(f(1) = 0\) \(\lim_{x \to 1} f(x) = \lim_{x \to 1} \frac{x^2+2 x-3}{x-1} = \lim_{x \to 1} \frac{(x+3)(x-1)}{x-1} = \lim_{x \to 1} (x+3) = 1+3 = 4\) Since \(\lim_{x \to 1} f(x) \neq f(1)\), the function is discontinuous at \(x=1\).
From CUET
Explore more questions on app