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CUET · MATHS · PYQ PAPER 2023

The function \(f: R \rightarrow R, f(x)=x^2\) is :

  1. A injective but not surjective
  2. B surjective but not injective
  3. C injective as well as surjective
  4. D neither injective nor surjective
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Answer & Solution

Correct Answer

(D) neither injective nor surjective

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Detailed explanation

Given \(f(x)=x^2\). If \(f(x_1)=f(x_2) \implies x_1^2=x_2^2 \implies x_1=\pm x_2\). Not injective (e.g., \(f(2)=f(-2)=4\)). The codomain is \(R\). The range of \(f(x)=x^2\) is \([0, \infty)\). Since \([0, \infty) \neq R\), not surjective (e.g., \(y=-1\) has no pre-image in…
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