CUET · MATHS · PYQ PAPER 2025
The function \(f : R \rightarrow R\) defined by \(f(x)=\left\{\begin{array}{ll}x^2, & x \geq 1 \\ x, & x<1\end{array}\right.\) is
- A Continuous but not differentiable at \(x=1\)
- B Continuous and differentiable at \(x=1\)
- C Neither continuous nor differentiable at \(x=1\)
- D Continuous but not differentiable at \(x=0\)
Answer & Solution
Correct Answer
(A) Continuous but not differentiable at \(x=1\)
Step-by-step Solution
Detailed explanation
\(\lim_{x \to 1^-} f(x) = \lim_{x \to 1^-} x = 1\) \(\lim_{x \to 1^+} f(x) = \lim_{x \to 1^+} x^2 = 1^2 = 1\) \(f(1) = 1^2 = 1\) Since \(\lim_{x \to 1^-} f(x) = \lim_{x \to 1^+} f(x) = f(1)\), \(f(x)\) is continuous at \(x=1\).…
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