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CUET · MATHS · PYQ PAPER 2025

The function \(f : R \rightarrow R\) defined by \(f(x)=\left\{\begin{array}{ll}x^2, & x \geq 1 \\ x, & x<1\end{array}\right.\) is

  1. A Continuous but not differentiable at \(x=1\)
  2. B Continuous and differentiable at \(x=1\)
  3. C Neither continuous nor differentiable at \(x=1\)
  4. D Continuous but not differentiable at \(x=0\)
Verified Solution

Answer & Solution

Correct Answer

(A) Continuous but not differentiable at \(x=1\)

Step-by-step Solution

Detailed explanation

\(\lim_{x \to 1^-} f(x) = \lim_{x \to 1^-} x = 1\) \(\lim_{x \to 1^+} f(x) = \lim_{x \to 1^+} x^2 = 1^2 = 1\) \(f(1) = 1^2 = 1\) Since \(\lim_{x \to 1^-} f(x) = \lim_{x \to 1^+} f(x) = f(1)\), \(f(x)\) is continuous at \(x=1\).…
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