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CUET · MATHS · PYQ PAPER 2023

The function \(f:[0,1] \rightarrow R\) given by \(f(x)=\alpha x^3\) has:

  1. A maximum value \(\frac{1}{8}\) when \(\alpha=1\)
  2. B minimum value \(-\frac{1}{8}\) when \(\alpha=-1\)
  3. C minimum value -1 when \(\alpha=-1\)
  4. D maximum value 1 when \(\alpha=-1\)
Verified Solution

Answer & Solution

Correct Answer

(C) minimum value -1 when \(\alpha=-1\)

Step-by-step Solution

Detailed explanation

For \(\alpha=-1\), \(f(x)=-x^3\). Since \(x^3\) is increasing on \([0,1]\), \(-x^3\) is decreasing on \([0,1]\). Minimum value at \(x=1\): \(f(1) = -(1)^3 = -1\).
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