CUET · MATHS · PYQ PAPER 2023
The equation of the tangent, to the curve \(y=x^2-2 x-3\) which is perpendicular to the line x + 2y + 3 = 0, is:
- A 4x - 2y = 7
- B 2x - y = 7
- C 2x - y = 5
- D 4x - 2y = 5
Answer & Solution
Correct Answer
(B) 2x - y = 7
Step-by-step Solution
Detailed explanation
\(m_{line} = -\frac{1}{2}\) \(m_{tangent} = -\frac{1}{m_{line}} = 2\) \(\frac{dy}{dx} = 2x - 2\) \(2x - 2 = 2 \Rightarrow 2x = 4 \Rightarrow x = 2\) \(y = (2)^2 - 2(2) - 3 = -3\) \(y - (-3) = 2(x - 2)\) \(y + 3 = 2x - 4\) \(2x - y = 7\)
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