CUET · MATHS · PYQ PAPER 2025
The equation of the tangent line to \(y=2 x^2+7\) , which is parallel to the line \(4 x-y+3=0\) is
- A \(4 x-y+7=0\)
- B \(4 x-y+3=0\)
- C \(4 x-y+5=0\)
- D \(4 x-y+1=0\)
Answer & Solution
Correct Answer
(C) \(4 x-y+5=0\)
Step-by-step Solution
Detailed explanation
\(m = 4\) \(\frac{dy}{dx} = 4x\) \(4x = 4 \implies x = 1\) \(y = 2(1)^2+7 = 9\) \(y - 9 = 4(x - 1)\) \(y - 9 = 4x - 4\) \(4x - y + 5 = 0\)
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