CUET · MATHS · PYQ PAPER 2023
The equation of the normal to the curve \(y=\frac{x-7}{(x-2)(x-3)}\) at (7,0) is:
- A 20x - y + 140 = 0
- B x + y + 140 = 0
- C x - 20y - 7 = 0
- D 20x + y - 140 = 0
Answer & Solution
Correct Answer
(D) 20x + y - 140 = 0
Step-by-step Solution
Detailed explanation
\(\frac{dy}{dx} = \frac{d}{dx}\left(\frac{x-7}{(x-2)(x-3)}\right) = \frac{(x^2-5x+6)(1) - (x-7)(2x-5)}{((x-2)(x-3))^2}\)…
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