CUET · MATHS · PYQ PAPER 2023
The equation of the normal to the curve \(y=x^4-6 x^3+13 x^2-10 x+5\) at \(x=1\) is:
- A \(2 x-y-1=0\)
- B \(x+2 y+7=0\)
- C \(2 x-y+1=0\)
- D \(x+2 y-7=0\)
Answer & Solution
Correct Answer
(D) \(x+2 y-7=0\)
Step-by-step Solution
Detailed explanation
\(y(1) = (1)^4 - 6(1)^3 + 13(1)^2 - 10(1) + 5 = 3\) Point: \((1, 3)\) \(\frac{dy}{dx} = 4x^3 - 18x^2 + 26x - 10\) \(m_t = 4(1)^3 - 18(1)^2 + 26(1) - 10 = 2\) \(m_n = -\frac{1}{m_t} = -\frac{1}{2}\) \(y - 3 = -\frac{1}{2}(x - 1)\) \(2(y - 3) = -(x - 1)\) \(2y - 6 = -x + 1\)…
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