CUET · MATHS · PYQ PAPER 2023
The equation of the line (in Cartesian form) which passes through the point \((-2,4,5)\) and parallel to the line given by \(\frac{x+3}{3}=\frac{y-4}{5}=\frac{z+8}{6}\) is:
- A \(\frac{x+2}{3}=\frac{y-4}{5}=\frac{z-5}{6}\)
- B \(\frac{x-2}{3}=\frac{y+4}{-5}=\frac{z-5}{6}\)
- C \(\frac{x+2}{4}=\frac{y+4}{3}=\frac{z-5}{-6}\)
- D \(\frac{x-2}{-3}=\frac{y-4}{5}=\frac{z-5}{5}\)
Answer & Solution
Correct Answer
(A) \(\frac{x+2}{3}=\frac{y-4}{5}=\frac{z-5}{6}\)
Step-by-step Solution
Detailed explanation
Equation of line: \(\frac{x-x_1}{a}=\frac{y-y_1}{b}=\frac{z-z_1}{c}\) Given point \((x_1,y_1,z_1) = (-2,4,5)\) Direction ratios from parallel line \((a,b,c) = (3,5,6)\) \(\frac{x-(-2)}{3}=\frac{y-4}{5}=\frac{z-5}{6}\) \(\frac{x+2}{3}=\frac{y-4}{5}=\frac{z-5}{6}\)
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