CUET · MATHS · PYQ PAPER 2023
The equation of perpendicular from the point \((1,0,1)\) to the plane \(x-y+z=4\) is
- A \(\frac{x-1}{2}=\frac{y}{-1}=\frac{z-1}{2}\)
- B \(\frac{x-1}{1}=\frac{y}{-1}=\frac{z-1}{1}\)
- C \(\frac{x-1}{1}=\frac{y-3}{-1}=\frac{z-2}{1}\)
- D \(\frac{x-1}{2}=\frac{y}{1}=\frac{z-1}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{x-1}{1}=\frac{y}{-1}=\frac{z-1}{1}\)
Step-by-step Solution
Detailed explanation
Direction ratios of normal to plane \(x-y+z=4\) are \((1, -1, 1)\). Equation of line passing through \((1,0,1)\) with direction ratios \((1, -1, 1)\) is \(\frac{x-1}{1} = \frac{y-0}{-1} = \frac{z-1}{1}\). \(\frac{x-1}{1} = \frac{y}{-1} = \frac{z-1}{1}\).
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