CUET · MATHS · PYQ PAPER 2023
The equation of a curve passing through the point \((-1,3)\), given that the slope of the tangent to the curve at any point \((x, y)\) is \(\frac{2 x}{y^2}\), is :
- A \(y=\left(3 x^2+24\right)^{\frac{1}{3}}\)
- B \(y=\left(3 x^2+30\right)^{\frac{1}{3}}\)
- C \(y=\left(x^2+24\right)^{\frac{1}{3}}\)
- D \(y=3 x^2-24\)
Answer & Solution
Correct Answer
(A) \(y=\left(3 x^2+24\right)^{\frac{1}{3}}\)
Step-by-step Solution
Detailed explanation
\(\frac{dy}{dx} = \frac{2x}{y^2}\) \(\int y^2 dy = \int 2x dx\) \(\frac{y^3}{3} = x^2 + C\) \(\frac{(3)^3}{3} = (-1)^2 + C \Rightarrow 9 = 1 + C \Rightarrow C = 8\) \(\frac{y^3}{3} = x^2 + 8\) \(y^3 = 3x^2 + 24\) \(y = (3x^2 + 24)^{\frac{1}{3}}\)
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