CUET · MATHS · PYQ PAPER 2023
The distance of a point \((1, -1, 0)\) from the plane \(\vec{r} \cdot (3\hat{i} - 2\hat{j} - 6\hat{k}) = 4\) is:
- A \(\frac{1}{7}\)
- B \(\frac{9}{7}\)
- C \(\frac{5}{7}\)
- D \(\frac{6}{7}\)
Answer & Solution
Correct Answer
(B) \(\frac{9}{7}\)
Step-by-step Solution
Detailed explanation
Distance \(d = \frac{|Ax_1 + By_1 + Cz_1 - D|}{\sqrt{A^2 + B^2 + C^2}}\) \(d = \frac{|(3)(1) + (-2)(-1) + (-6)(0) - 4|}{\sqrt{(3)^2 + (-2)^2 + (-6)^2}}\) \(d = \frac{|3 + 2 - 4|}{\sqrt{9 + 4 + 36}}\) \(d = \frac{|1|}{\sqrt{49}}\) \(d = \frac{1}{7}\)
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