CUET · MATHS · PYQ PAPER 2023

The Differential Equation representing the family of tangents to the circle \(x^2+y^2=r^2\)is:

A \(\frac{d y}{d x}=0\)
B \(\frac{d^2 y}{d x^2}=0\)
C \(\frac{d y}{d x}=a\)
D \(\frac{d^2 y}{d x^2}=a\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{d^2 y}{d x^2}=0\)

Step-by-step Solution

Detailed explanation

\(y = mx \pm r\sqrt{1+m^2}\) \(\frac{dy}{dx} = m\) \(\frac{d^2y}{dx^2} = 0\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

If \(f(x)=\left\{\begin{array}{ll}\frac{\sin \pi x}{5 x}, & x \neq 0 \\ k, & x=0\end{array}\right.\) is continuous at \(x=0\), then \(k\) is :

CUET 2023 Hard

Match List - I With List - II

List - I	List - II
(A) The area of parallelogram determined by vectors \(2 \hat{i}\) and \(3 \hat{j}\)	(I) 2
(B) The value of \((\hat{i} \times \hat{j}) \cdot \hat{k}+(\hat{j} \times \hat{k}) \cdot \hat{i}\)	(II) 4
(C) The value of a for which the vectors \(2 \hat{i}-3 \hat{j}+4 \hat{k}\) and \(a \hat{i}-6 \hat{j}+8 \hat{k}\) are collinear.	(III) 0
D. The value of \(\lambda\) for which the vectors \(2 \hat{i}+\hat{j}+\hat{k}\) and \(2 \hat{i}-4 \hat{j}+\lambda \hat{k}\) are perpendicular.	(IV) 6

Choose the correct answer from the options given below.

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