CUET · MATHS · PYQ PAPER 2023
The derivative of \(\cos ^{-1}\left(\frac{\sin x+\cos x}{\sqrt{2}}\right),-\frac{\pi}{4} < x < \frac{\pi}{4}\) with respect to \(x\) is :
- A \(\frac{1}{\sqrt{2}}\)
- B 1
- C \(-1\)
- D \(\frac{-1}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(C) \(-1\)
Step-by-step Solution
Detailed explanation
\(y = \cos ^{-1}\left(\frac{1}{\sqrt{2}}\sin x+\frac{1}{\sqrt{2}}\cos x\right)\) \(y = \cos ^{-1}\left(\sin\left(x+\frac{\pi}{4}\right)\right)\) \(y = \cos ^{-1}\left(\cos\left(\frac{\pi}{2}-\left(x+\frac{\pi}{4}\right)\right)\right)\)…
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