CUET · MATHS · PYQ PAPER 2025
The demand for a certain product is represented by the function \(p=300+25 x-x^2\) (in rupees), where \(x\) is the number of units demanded and \(p\) is the price per unit, then the marginal revenue when 15 units are sold, is
- A ₹ 675
- B ₹ 375
- C ₹ 1050
- D ₹ 775
Answer & Solution
Correct Answer
(B) ₹ 375
Step-by-step Solution
Detailed explanation
\(R(x) = p \cdot x = (300 + 25x - x^2)x = 300x + 25x^2 - x^3\) \(MR(x) = \frac{dR}{dx} = \frac{d}{dx}(300x + 25x^2 - x^3) = 300 + 50x - 3x^2\) \(MR(15) = 300 + 50(15) - 3(15)^2\) \(MR(15) = 300 + 750 - 3(225)\) \(MR(15) = 300 + 750 - 675 = 375\)
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