CUET · MATHS · PYQ PAPER 2025
The demand for a certain product is represented by the function
\(p=150+10 x-x^2 \text { (in Rs.) }\)
where \(x\) is the number of units demanded and \(p\) is the price per unit, then the value of marginal revenue, when 10 units are sold, is
- A Rs. 50
- B Rs. 100
- C Rs. 150
- D Rs. 200
Answer & Solution
Correct Answer
(A) Rs. 50
Step-by-step Solution
Detailed explanation
Total Revenue \(R = px = (150 + 10x - x^2)x = 150x + 10x^2 - x^3\) Marginal Revenue \(MR = \frac{dR}{dx} = \frac{d}{dx}(150x + 10x^2 - x^3) = 150 + 20x - 3x^2\) For \(x=10\), \(MR = 150 + 20(10) - 3(10)^2\) \(MR = 150 + 200 - 3(100)\) \(MR = 350 - 300\) \(MR = 50\)
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