CUET · MATHS · PYQ PAPER 2023
The corner points of the feasible region determined by the following system of linear inequalities \(2 x+y \leq 10, x+3 y \leq 15, x, y \geq 0\) are \((0,0),(5,0),(3,4)\) and \((0,5)\). Let \(z=p x+q y\) where \(p\) and \(q>0\). The condition on \(p\) and \(q\) so that the maximum of \(z\) occurs at both \((3,4)\) and \((0,5)\) is :
- A \(p=q\)
- B \(p=2 q\)
- C \(p=3 q\)
- D \(q=3 p\)
Answer & Solution
Correct Answer
(D) \(q=3 p\)
Step-by-step Solution
Detailed explanation
Value of \(z\) at \((3,4)\): \(z_1 = p(3) + q(4) = 3p + 4q\) Value of \(z\) at \((0,5)\): \(z_2 = p(0) + q(5) = 5q\) For maximum to occur at both points: \(z_1 = z_2\) \(3p + 4q = 5q\) \(3p = q\)
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