CUET · MATHS · PYQ PAPER 2025
The corner points of the bounded feasible region determined by the system of linear inequalities are (0, 0), (4, 0), (2, 4) and (0, 5). If maximum value of z = ax + by, where a, b > 0 occurs at both (2, 4) and (4, 0) then
- A a = 2b
- B 2a = b
- C a = b
- D 3a = b
Answer & Solution
Correct Answer
(A) a = 2b
Step-by-step Solution
Detailed explanation
Value of \( z \) at (2, 4): \( z_1 = a(2) + b(4) = 2a + 4b \) Value of \( z \) at (4, 0): \( z_2 = a(4) + b(0) = 4a \) Since maximum occurs at both points: \( 2a + 4b = 4a \) \( 4b = 2a \) \( a = 2b \)
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