CUET · MATHS · PYQ PAPER 2023
The coordinates of the point where the line \(\frac{x-3}{2}=\frac{y-4}{-3}=\frac{z-1}{5}\) crosses \(X Y\) plane is :
- A \(\left(\frac{23}{5}, \frac{13}{5}, 0\right)\)
- B \(\left(\frac{13}{5}, \frac{23}{5}, 0\right)\)
- C \(\left(0, \frac{23}{5}, \frac{13}{5}\right)\)
- D \(\left(\frac{23}{5}, 0, \frac{13}{5}\right)\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{13}{5}, \frac{23}{5}, 0\right)\)
Step-by-step Solution
Detailed explanation
For XY plane, \(z=0\). \(\frac{0-1}{5} = -\frac{1}{5}\) \(\frac{x-3}{2} = -\frac{1}{5} \Rightarrow 5(x-3)=-2 \Rightarrow 5x-15=-2 \Rightarrow 5x=13 \Rightarrow x=\frac{13}{5}\)…
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