CUET · MATHS · PYQ PAPER 2023
The area of the smaller portion enclosed by the circle \(x^2+y^2=4\) and the straight line \(x+y=2\) is:
- A \(\pi+2\)
- B \(\pi-2\)
- C \(2-\pi\)
- D \(-\pi-2\)
Answer & Solution
Correct Answer
(B) \(\pi-2\)
Step-by-step Solution
Detailed explanation
Area of sector \(= \frac{1}{4}\pi r^2 = \frac{1}{4}\pi (2)^2 = \pi\) Area of triangle \(= \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2}(2)(2) = 2\) Area of smaller portion \(= \text{Area of sector} - \text{Area of triangle} = \pi - 2\)
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