CUET · MATHS · PYQ PAPER 2025
The area of the region (in square units) bounded by \(x=1, x=2\) and the curve \(y^2=4 x\) in the first quadrant is:
- A \(\frac{4}{3}[2 \sqrt{2}-1]\)
- B \(\frac{2}{3}[2 \sqrt{2}-1]\)
- C \(\frac{2}{3}[2 \sqrt{2}+1]\)
- D \(\frac{4}{3}[2 \sqrt{2}+1]\)
Answer & Solution
Correct Answer
(A) \(\frac{4}{3}[2 \sqrt{2}-1]\)
Step-by-step Solution
Detailed explanation
\(A = \int_{1}^{2} \sqrt{4x} \, dx\) \(A = \int_{1}^{2} 2\sqrt{x} \, dx\) \(A = 2 \left[ \frac{x^{3/2}}{3/2} \right]_{1}^{2}\) \(A = \frac{4}{3} [x^{3/2}]_{1}^{2}\) \(A = \frac{4}{3} [2^{3/2} - 1^{3/2}]\) \(A = \frac{4}{3} [2\sqrt{2} - 1]\)
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