CUET · MATHS · PYQ PAPER 2025
The area of the region bounded by \(y^2=9 x, x=2, x=4\) and the \(x\)-axis in the first quadrant, is
- A \(16-\sqrt{2}\) sq. units
- B \(16+\sqrt{2}\) sq. units
- C \(16+4 \sqrt{2}\) sq. units
- D \(16-4 \sqrt{2}\) sq. units
Answer & Solution
Correct Answer
(D) \(16-4 \sqrt{2}\) sq. units
Step-by-step Solution
Detailed explanation
\(y = 3\sqrt{x}\) \(A = \int_{2}^{4} 3x^{1/2} \, dx\) \(A = \left[ 2x^{3/2} \right]_{2}^{4}\) \(A = 2(4^{3/2} - 2^{3/2})\) \(A = 2(8 - 2\sqrt{2})\) \(A = 16 - 4\sqrt{2}\)
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