CUET · MATHS · PYQ PAPER 2023
The area of the region bounded by \(y^2=2 x+1\) and x - y = 1 is:
- A 3 sq. units
- B 16 sq. units
- C \(\frac{14}{3}\) sq. units
- D \(\frac{16}{3}\) sq. units
Answer & Solution
Correct Answer
(D) \(\frac{16}{3}\) sq. units
Step-by-step Solution
Detailed explanation
\(x = y+1\) \(y^2 = 2(y+1)+1 \Rightarrow y^2-2y-3=0\) \((y-3)(y+1)=0 \Rightarrow y=-1, 3\) Area \(A = \int_{-1}^{3} \left( (y+1) - \left(\frac{y^2-1}{2}\right) \right) dy\) \(A = \int_{-1}^{3} \left( -\frac{y^2}{2} + y + \frac{3}{2} \right) dy\)…
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