CUET · MATHS · PYQ PAPER 2023
The area of the region bounded by \(x^2=4 y\) and \(x=4 y-2\) (in sq. units) is:
- A \(\frac{8}{9}\)
- B \(\frac{4}{9}\)
- C \(\frac{2}{9}\)
- D \(\frac{9}{8}\)
Answer & Solution
Correct Answer
(D) \(\frac{9}{8}\)
Step-by-step Solution
Detailed explanation
\(x^2=4y \implies y_P=\frac{x^2}{4}\) \(x=4y-2 \implies y_L=\frac{x+2}{4}\) \(\frac{x^2}{4} = \frac{x+2}{4}\) \(x^2 - x - 2 = 0\) \((x-2)(x+1) = 0 \implies x_1=-1, x_2=2\) \(y_L - y_P = \frac{x+2}{4} - \frac{x^2}{4} = -\frac{1}{4}x^2+\frac{1}{4}x+\frac{1}{2}\)…
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