CUET · MATHS · PYQ PAPER 2025
The area of the region bounded by the parabola \(y^2=8 x\) and its latus rectum in the first quadrant, is
- A \(\frac{8}{3}\) sq. units
- B \(\frac{32}{3}\) sq. units
- C \(\frac{16 \sqrt{2}}{3}\) sq. units
- D \(\frac{16}{3}\) sq. units
Answer & Solution
Correct Answer
(D) \(\frac{16}{3}\) sq. units
Step-by-step Solution
Detailed explanation
\(y^2=8x \implies 4a=8 \implies a=2\) Latus rectum is \(x=a \implies x=2\) Area \(A = \int_{0}^{2} \sqrt{8x} \, dx\) \(A = \int_{0}^{2} 2\sqrt{2}x^{1/2} \, dx = 2\sqrt{2} \left[ \frac{2}{3}x^{3/2} \right]_{0}^{2}\)…
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