CUET · MATHS · PYQ PAPER 2023
The area of the parallelogram determined by the vectors \(\hat{i}+2 \hat{j}+3 \hat{k}\) and \(3 \hat{i}-2 \hat{j}+\hat{k}\) is
- A \(8 \sqrt{3}\)
- B \(4 \sqrt{3}\)
- C \(16 \sqrt{3}\)
- D \(2 \sqrt{3}\)
Answer & Solution
Correct Answer
(A) \(8 \sqrt{3}\)
Step-by-step Solution
Detailed explanation
\(\vec{a} \times \vec{b} = ((2)(1)-(3)(-2))\hat{i} - ((1)(1)-(3)(3))\hat{j} + ((1)(-2)-(2)(3))\hat{k}\) \(= (2+6)\hat{i} - (1-9)\hat{j} + (-2-6)\hat{k}\) \(= 8\hat{i} + 8\hat{j} - 8\hat{k}\) \(\text{Area} = |\vec{a} \times \vec{b}| = \sqrt{8^2+8^2+(-8)^2}\)…
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