CUET · MATHS · PYQ PAPER 2025
The area of a triangle whose vertices are \(\left(x_1, y_1\right),\left(x_2, y_2\right)\) and \(\left(x_3, y_3\right)\) is given by the absolute value of
- A \(\Delta=\frac{1}{2}\left|\begin{array}{lll}x_1 & y_1 & 1 \\ x_2 & y_2 & 1 \\ x_3 & y_3 & 1\end{array}\right|\)
- B \(\Delta=\left|\begin{array}{lll}x_1 & y_1 & 1 \\ x_2 & y_2 & 1 \\ x_3 & y_3 & 1\end{array}\right|\)
- C \(\Delta=\frac{1}{2}\left|\begin{array}{lll}x_1 & y_1 & 1 \\ x_2 & y_2 & 0 \\ x_3 & y_3 & 0\end{array}\right|\)
- D \(\Delta=\left|\begin{array}{lll}x_1 & y_1 & 1 \\ x_2 & y_2 & 0 \\ x_3 & y_3 & 0\end{array}\right|\)
Answer & Solution
Correct Answer
(A) \(\Delta=\frac{1}{2}\left|\begin{array}{lll}x_1 & y_1 & 1 \\ x_2 & y_2 & 1 \\ x_3 & y_3 & 1\end{array}\right|\)
Step-by-step Solution
Detailed explanation
\(\Delta=\frac{1}{2}\left|\begin{array}{lll}x_1 & y_1 & 1 \\ x_2 & y_2 & 1 \\ x_3 & y_3 & 1\end{array}\right|\)
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