CUET · MATHS · PYQ PAPER 2023
The area of a triangle having the points \(A (1,1,1), B (1,2,3)\) and \(C (2,3,1)\) as its vertices is :
- A \(\sqrt{21}\)
- B \(2 \sqrt{21}\)
- C \(\frac{1}{4} \sqrt{21}\)
- D \(\frac{1}{2} \sqrt{21}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{2} \sqrt{21}\)
Step-by-step Solution
Detailed explanation
\(\vec{AB} = B - A = (1-1, 2-1, 3-1) = (0, 1, 2)\) \(\vec{AC} = C - A = (2-1, 3-1, 1-1) = (1, 2, 0)\) \(\vec{AB} \times \vec{AC} = (1 \cdot 0 - 2 \cdot 2)\hat{i} - (0 \cdot 0 - 2 \cdot 1)\hat{j} + (0 \cdot 2 - 1 \cdot 1)\hat{k} = -4\hat{i} + 2\hat{j} - \hat{k}\)…
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