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CUET · MATHS · PYQ PAPER 2023

The area lying between the curves \(y^2=4 x\) and \(y=2 x\) is :

  1. A \(\frac{2}{3}\)
  2. B 1
  3. C \(\frac{1}{3}\)
  4. D \(\frac{1}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{3}\)

Step-by-step Solution

Detailed explanation

\((2x)^2 = 4x \Rightarrow 4x^2 - 4x = 0 \Rightarrow 4x(x-1) = 0 \Rightarrow x=0, 1\) \(A = \int_{0}^{1} (2\sqrt{x} - 2x) dx\) \(A = \left[ \frac{4}{3}x^{3/2} - x^2 \right]_{0}^{1} = \left( \frac{4}{3}(1)^{3/2} - (1)^2 \right) - (0) = \frac{4}{3} - 1 = \frac{1}{3}\)