CUET · MATHS · PYQ PAPER 2025
The area (in square units) of the region bounded by the curve \(x^2=y\) and the straight line \(y=4\) in the first quadrant is equal to
- A \(\frac{3}{2}\)
- B \(\frac{16}{3}\)
- C \(\frac{32}{3}\)
- D \(\frac{7}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{16}{3}\)
Step-by-step Solution
Detailed explanation
Area \(A = \int_{0}^{2} (4 - x^2) dx\) \(= \left[ 4x - \frac{x^3}{3} \right]_{0}^{2}\) \(= \left( 4(2) - \frac{2^3}{3} \right) - 0 = 8 - \frac{8}{3} = \frac{16}{3}\)
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