CUET · MATHS · PYQ PAPER 2025
The area (in sq. units) of the triangle whose vertices are \((0,0),(a, 0),(0, b)\), is equal to
- A \(a^2\)
- B \(|a b|\)
- C \(\frac{1}{2}|a b|\)
- D \(b^2\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2}|a b|\)
Step-by-step Solution
Detailed explanation
Area \( = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|\) Area \( = \frac{1}{2} |0(0 - b) + a(b - 0) + 0(0 - 0)|\) Area \( = \frac{1}{2} |ab|\)
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