CUET · MATHS · PYQ PAPER 2025
The area (in sq. units) of the region bounded by \(y=2 x+3\), the \(x\)-axis, and the ordinates \(x=-2, x=2\) is equal to
- A 12
- B \(\frac{49}{4}\)
- C \(\frac{25}{2}\)
- D 25
Answer & Solution
Correct Answer
(C) \(\frac{25}{2}\)
Step-by-step Solution
Detailed explanation
\(x\)-intercept: \(2x+3=0 \Rightarrow x = -3/2\). Area \(A = \int_{-2}^{2} |2x+3| dx = \int_{-2}^{-3/2} -(2x+3) dx + \int_{-3/2}^{2} (2x+3) dx\). \(A = [-x^2 - 3x]_{-2}^{-3/2} + [x^2 + 3x]_{-3/2}^{2}\).…
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