CUET · MATHS · PYQ PAPER 2025
The area (in sq. units) of the region bounded by \(y=-1, y=2, x=y^3\) and \(x=0\) is equal to
- A 4
- B 8
- C \(\frac{17}{4}\)
- D \(\frac{15}{4}\)
Answer & Solution
Correct Answer
(C) \(\frac{17}{4}\)
Step-by-step Solution
Detailed explanation
Area \( = \int_{-1}^{0} (0 - y^3) dy + \int_{0}^{2} (y^3 - 0) dy \) \( = [-\frac{y^4}{4}]_{-1}^{0} + [\frac{y^4}{4}]_{0}^{2} \) \( = (0 - (-\frac{1}{4})) + (\frac{16}{4} - 0) = \frac{1}{4} + 4 = \frac{17}{4} \)
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