CUET · MATHS · PYQ PAPER 2025
The area (in sq. units) of the bigger portion of region enclosed by the curves \(4 x^2+9 y^2=36\) and \(2 x+3 y=6\) is
- A \(\frac{3}{2}(\pi-2)\)
- B \(\frac{3}{2}(3 \pi+2)\)
- C \((6 \pi)\)
- D \((3 \pi+3)\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{2}(3 \pi+2)\)
Step-by-step Solution
Detailed explanation
Ellipse: \(4 x^2+9 y^2=36 \implies \frac{x^2}{3^2} + \frac{y^2}{2^2} = 1\) Total area of ellipse: \(A_{ellipse} = \pi (3)(2) = 6\pi\) Line \(2 x+3 y=6\) intercepts ellipse at \((3,0)\) and \((0,2)\). Area of triangle formed by line segment \((3,0)-(0,2)\) and axes:…
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