CUET · MATHS · PYQ PAPER 2025
The area (in sq. units) bounded by the parabola \(y^2=16 x\) and its latus rectum is
- A 64 Sq. units
- B \(\frac{32}{3}\) Sq. units
- C \(\frac{64}{3}\) Sq. units
- D \(\frac{128}{3}\) Sq. units
Answer & Solution
Correct Answer
(D) \(\frac{128}{3}\) Sq. units
Step-by-step Solution
Detailed explanation
\(y^2=16x \Rightarrow 4a=16 \Rightarrow a=4\) Latus rectum is \(x=4\) \(Area = 2 \int_{0}^{4} 4\sqrt{x} \,dx = 8 \int_{0}^{4} x^{1/2} \,dx\) \(Area = 8 \left[ \frac{2}{3}x^{3/2} \right]_{0}^{4} = \frac{16}{3} (4^{3/2} - 0)\) \(Area = \frac{16}{3} (8) = \frac{128}{3}\) Sq. units
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