CUET · MATHS · PYQ PAPER 2025
The area (in sq. units) bounded by the parabola \(y^2=4 a x\), its latus rectum and the \(x\)-axis in the first quadrant is:
- A \(\frac{1}{3} a^2\)
- B \(\frac{2}{3} a^2\)
- C \(\frac{4}{3} a^2\)
- D \(\frac{8}{3} a^2\)
Answer & Solution
Correct Answer
(C) \(\frac{4}{3} a^2\)
Step-by-step Solution
Detailed explanation
\(y = \sqrt{4ax} = 2\sqrt{a}\sqrt{x}\) \(Area = \int_{0}^{a} 2\sqrt{a}\sqrt{x} dx\) \(Area = 2\sqrt{a} \left[ \frac{x^{3/2}}{3/2} \right]_{0}^{a}\) \(Area = 2\sqrt{a} \cdot \frac{2}{3} \left[ x^{3/2} \right]_{0}^{a}\) \(Area = \frac{4}{3}\sqrt{a} (a^{3/2} - 0^{3/2})\)…
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