CUET · MATHS · PYQ PAPER 2023
The area enclosed between \(y^2=4 x\) and \(x^2=4 y\) is:
- A \(\frac{8}{3}\) sq. units
- B \(\frac{4}{3}\) sq. units
- C \(\frac{2}{3}\) sq. units
- D \(\frac{16}{3}\) sq. units
Answer & Solution
Correct Answer
(D) \(\frac{16}{3}\) sq. units
Step-by-step Solution
Detailed explanation
Intersection points: \(y^2=4x \Rightarrow x = y^2/4\) \((y^2/4)^2 = 4y \Rightarrow y^4/16 = 4y \Rightarrow y^4 - 64y = 0\) \(y(y^3 - 64) = 0 \Rightarrow y=0, y=4\) For \(y=0, x=0\). For \(y=4, x=4\). Area \(A = \int_{0}^{4} (2\sqrt{x} - \frac{x^2}{4}) dx\)…
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