CUET · MATHS · PYQ PAPER 2023
The area bounded by \(y^2=4 x\) and its latus rectum and \(x\)-axis in the first quadrant is:
- A 0 sq. units
- B \(\frac{4}{3}\) sq. units
- C \(\frac{2}{3}\) sq. units
- D \(\frac{1}{3}\) sq. units
Answer & Solution
Correct Answer
(B) \(\frac{4}{3}\) sq. units
Step-by-step Solution
Detailed explanation
Parabola: \(y^2=4x\), so \(a=1\). Latus rectum: \(x=1\). Area \( = \int_{0}^{1} 2\sqrt{x} \, dx \) \( = 2 \left[ \frac{x^{3/2}}{3/2} \right]_{0}^{1} \) \( = \frac{4}{3} [x^{3/2}]_{0}^{1} \) \( = \frac{4}{3} (1^{3/2} - 0^{3/2}) = \frac{4}{3} \) sq. units.
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