CUET · MATHS · PYQ PAPER 2025
The area bounded by the curve \(y=4+3 x-x^2\) and the \(x\)-axis is equal to
- A \(\frac{125}{6}\) Sq. units
- B \(\frac{125}{3}\) Sq. units
- C \(\frac{125}{2}\) Sq. units
- D \(\frac{121}{6}\) Sq. units
Answer & Solution
Correct Answer
(A) \(\frac{125}{6}\) Sq. units
Step-by-step Solution
Detailed explanation
\(4+3x-x^2 = 0 \Rightarrow x^2-3x-4=0 \Rightarrow (x-4)(x+1)=0 \Rightarrow x = -1, 4\) \(A = \int_{-1}^{4} (4+3x-x^2)dx\) \(A = [4x + \frac{3x^2}{2} - \frac{x^3}{3}]_{-1}^{4} = (16+24-\frac{64}{3}) - (-4+\frac{3}{2}+\frac{1}{3})\)…
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