CUET · MATHS · PYQ PAPER 2023
The angle between two vectors \(\vec{a}\) and \(\vec{b}\) with magnitudes \(\sqrt{3}\) and 4 respectively and \(\vec{a} \cdot \vec{b}=2 \sqrt{3}\) is :
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{2}\)
- D \(\frac{\pi}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
\(\cos\theta = \frac{\vec{a} \cdot \vec{b}}{|\vec{a}| |\vec{b}|}\) \(\cos\theta = \frac{2\sqrt{3}}{\sqrt{3} \cdot 4}\) \(\cos\theta = \frac{1}{2}\) \(\theta = \frac{\pi}{3}\)
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