CUET · MATHS · PYQ PAPER 2023
The angle between thee curves \(x y=\sqrt{2}\) and \(x^2-y^2=1\) at \((\sqrt{2}, 1)\) is:
- A \(30^{\circ}\)
- B \(45^{\circ}\)
- C \(60^{\circ}\)
- D \(90^{\circ}\)
Answer & Solution
Correct Answer
(D) \(90^{\circ}\)
Step-by-step Solution
Detailed explanation
\(C_1: xy = \sqrt{2} \implies y' = -\frac{y}{x}\) \(m_1 = -\frac{1}{\sqrt{2}}\) at \((\sqrt{2}, 1)\) \(C_2: x^2 - y^2 = 1 \implies 2x - 2yy' = 0 \implies y' = \frac{x}{y}\) \(m_2 = \frac{\sqrt{2}}{1} = \sqrt{2}\) at \((\sqrt{2}, 1)\)…
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